Population 1000
1. √.49 to get q which is .7
2. Subtract 1 from .7 to get p which is .3
3. Double check that q+p=1
4. Square p to get p² which is .09
5. Multiply p and q together which is .21 then multiply that by 2 which is .42 and that is the answer to 2pq
6. Double check that p²+2pq+q²= 1
Homozygous dominant individual (p²) = .09
Homozygous recessive individual (q²) = .49
Heterozygous individual (2pq) = .42
Frequency of dominant allele (p) = .3
Frequency of recessive allele (q) = .7
With a population of 1000 you could discover the...
Three possible genotypes:
Homozygous dominant individual (p²) = 90 (multiply .09 by 1000)
Homozygous recessive individual (q²) = 490 (multiply .49 by 1000)
Heterozygous individual (2pq) = 420 (multiply .42 by 1000)
And the...
Frequency of alleles:
Frequency of dominant allele (p) = 30%
Frequency of recessive allele (q) = 70%
And the...
Frequency of alleles:
Frequency of dominant allele (p) = 30%
Frequency of recessive allele (q) = 70%
I really like how you set up your blog. It's also really great that you have provided sufficient space between your different steps. Your steps are also very clearly written and they are very easy to understand.
ReplyDelete