Population 1000
1. √.49 to get q which is .7
2. Subtract 1 from .7 to get p which is .3
3. Double check that q+p=1
4. Square p to get p² which is .09
5. Multiply p and q together which is .21 then multiply that by 2 which is .42 and that is the answer to 2pq
6. Double check that p²+2pq+q²= 1
Homozygous dominant individual (p²) = .09
Homozygous recessive individual (q²) = .49
Heterozygous individual (2pq) = .42
Frequency of dominant allele (p) = .3
Frequency of recessive allele (q) = .7
With a population of 1000 you could discover the...
Three possible genotypes:
Homozygous dominant individual (p²) = 90 (multiply .09 by 1000)
Homozygous recessive individual (q²) = 490 (multiply .49 by 1000)
Heterozygous individual (2pq) = 420 (multiply .42 by 1000)
And the...
Frequency of alleles:
Frequency of dominant allele (p) = 30%
Frequency of recessive allele (q) = 70%
And the...
Frequency of alleles:
Frequency of dominant allele (p) = 30%
Frequency of recessive allele (q) = 70%